Find the area of the following figure. Assume that all lines that appear to be parallel are parallel. Round to the nearest tenth if necessary.

466in³

Step-by-step explanation:

Cut the figure in to two rectangles and one triangle. Draw an imaginary line like I did in the photo. Then solve the area of each one. First to solve the area of a, or the largest rectangle, multiply 29 by 10. You will get 290. Next, solve the area of b, or the small rectangle. Multiply 7 by 16, and you will get 112. Then, solve the area of the triangle. To get the length of the base of the triangle, subtract 10 and 7 from 25. The base length is 8. Solve the area of the triangle by multiplying 8 by 16 and then dividing by two. The area is 64. Finally, add all the areas. 290+112+64= 466. The area of the figure is 466in³.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it