The range of a projectile that is launched with an initial velocity v at an angle of theta with the horizontal is given by R=v^2/g sin 2 theta, where g is the acceleration due to gravity or 9.8 meters per second squared. If a projectile is launched with an initial velocity of 15 meters per second, what angle is required to achieve a range of 20 meters? Round answers to the nearest whole number.

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105

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step-by-step explanation:

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