Solve the following equation algebraically: Negative 16 = 16 x squared
How many solutions does this equation have? Explain.
a.
Negative 1 = x squared; One solution because only -1 will satisfy the equation.
b.
Negative 1 = x squared; No real solution because there is no real number that, when squared, produces -1.
c.
1 = x squared; Two solutions because the square root of 1 is positive 1 and negative 1.
d.
1 = negative x squared; One solution because only -1 will satisfy the equation.

Please select the best answer from the choices provided

A
B
C
D

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

idk lol xd

step-by-step explanation:

ez do it yourself lazy