Please help me with this problem about factoring.

2x^3(3x^3-5x^4+2)

Step-by-step explanation:

Given: 6x^6-10x^7+4x^3

Factor out x^3: x^3(6x^3-10x^4+4)

Factor out 2: 2x^3(3x^3-5x^4+2)

Always look for what you can factor out.

1/5^2 = 7.56/45

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.