F(x)=-2(x-4)^2+8 find the vertex

(4,8)

Step-by-step explanation:

The vertex form of the equation of a parabola that is a function of x is:

y = f(x) = a( x - h) ^2 + k

In the given equation, h = 4 and k = 8, therefore, the vertex is (4, 8)

Set the polynomial equal to

y

to find the properties of the parabola.

y = -3(x+4)^2 - 8

Use the vertex form, y = a (x-h)^2 + k, to determine values of a,h and k

a = -2

h = -4

k = -8

Find the vertex (h,k)

(-4, -8)

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

3

step-by-step explanation: