Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 ANSWER RIGHT NOW BEEN WAITING AN HOUR NOW Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 ANSWER RIGHT NOW BEEN WAITING AN HOUR NOW Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 ANSWER RIGHT NOW BEEN WAITING AN HOUR NOW

ii6tyhj7 juj3yyj333ju jmyhthhtk7h jg hajj jiijh

nswer: a   y-axis

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer