PLEASE HELP ASAP P(-5, 2), Q(4, 5), R(6, – 1), S(-3, -4)
this is a rectangle right and why is it and not rhombus or square?

It's a rectangle, but not a rhombus (or square).

Step-by-step explanation:

Let's see the vectors of each next vertex:

Firstly, we can notice that it's a parallelogram - because the Q-P side is parallel to the S - R side (if the x:y ratios are the same, the sides are parallel).

A rhombus needs the sides to be of the same length. But the length of a (x, y) vector is and , we don't even have to compute it exactly. If it's not a rhombus, it's also not a square (every square is a rhombus).

The last thing left is to know if it's a rectangle - for it to be a rectangle, we need to check if the vectors are perpendicular.

We can compute the dot product of the vectors - perpendicular vectors always have a dot product equal to zero. The dot product of two vectors and is equal to .

So the sides are perpendicular, and as such - the figure is a rectangle.

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step-by-step explanation:

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step-by-step explanation:

hope this