3. This spinner is divided into eight equal-sized sections. Each section is labeled with a number Jake spins the arrow on the spinner once.
Drag and drop the events into the correct order from least likely to most likely.

Least Likely: Arrow lands on a section labeled with an odd number.

: Arrow lands on a section labeled with the number 1.

Most Likely: Arrow lands on a section labeled with a number less than 4.

Step-by-step explanation:

The spinner:

There are 8 sections, 4 labeled with the number 1, 2 labeled with the number 3, 1 labeled with the number 3, and 1 labeled with the number 4.

Probabilities of the spinner:

The options:

A - Arrow lands on a section labeled with an odd number.

B - Arrow lands on a section labeled with the number 1.

C - Arrow lands on a section labeled with a number less than 4.

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.