There were 11 students running in a race how many different arrangements of first second and third place are possible

Explanation:

For first place, we have 11 choices

11 × __ × __

For second place, we have 10 choices

11 × 10 × __

And for third place, we have 9 choices

11 x 10 x 9 = 990 ways

This is also a permutation

11! / (11-3)! = 990

Hope it helps

2

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this