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1. Find the angle between the vectors:
i-23 + 5k and 3i+j - 2k

The angle between the two vectors

∝ = 64°

Step-by-step explanation:

Step(i):-

Given that the vectors

          and

           =  3 (i⁻ . i⁻) - 2(j⁻.j⁻) -10(k⁻.k⁻)

          = 3 - 2 -10

          = -9

Step(ii):-

Let '∝' be the angle between the two vectors

              ∝ = cos⁻¹(0.4392) = 63.947

Final -

The angle between the two vectors

               ∝ = cos⁻¹(0.4392) = 63.947

                ∝ = 64°

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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