Fritz is recording the decay of radioactive material. The table displays the number of weeks and the level of radioactivity he measures each week.
What will be the level of radioactivity in 10 weeks?

Every week, the radioactivity decreases by a factor of 5

After 1 week, it goes from 5,000 to 1,000

2 weeks  1,000 / 5 =200

3 weeks 200 / 5 = 40

4 weeks 40 / 5 = 8

5 weeks 8 / 5 = 1.6

6 weeks 1.6 / 5 = 0.064

7 weeks 0.064 / 5 = 0.0128

8 weeks .0128 / 5 = 0.00256

9 weeks 0.00256 / 5 = 0.000512

10 weeks 0.000512 / 5 = 0.0001024

Step-by-step explanation:

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.