11y^2-19y-10=-4y^2
all real solutions

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

|

| y = 5/3 or y = -2/5

b

step-by-step explanation:

if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!

ok now , i would like brainlest plz

dwe

step-by-step explanation:

ewd