What is the domain of the relation? On a coordinate plane, a graph of an image has 3 connected lines. The first line goes from (negative 4, negative 4) to (negative 2, 1). The second line goes from (negative 2, 1) to (1, 1). The third line goes from (1, 1) to (6, 4). There are closed circles at (negative 4, negative 4) and (6, 4).

Given:

The graph of a relation contains three lines.

The first line goes from (-4,-4) to (-2, 1).

The second line goes from (-2, 1) to (1, 1).

The third line goes from (1, 1) to (6, 4).

There are closed circles at (-4,-4) and (6, 4).

To find:

The domain of the relation.

Solution:

Domain of relation is the set of x-values or the set of input values.

First line is defined from -4 to -2, second line is defined from -2 to 1 and third line is defined from 1 to 6.

There are closed circles at (-4, -4) and (6, 4). It means -4 and -6 are included in the domain.

Since the input values for the given relation is from -4 to 6, where -4 and 6 are included, therefore the domain of the relation is [-4,6].

true

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3