Which is the vertex point of the equation y = (x - 1)2 - 16

The vertex is at (h, k), which here is (1, -16).

Step-by-step explanation:

Compare the given y = (x - 1)2 - 16          (which should be y = (x - 1)^2 - 16 )

to                               y = (x - h)^2 - 16.

We can readily see that h = 1 and k = -16.

The vertex is at (h, k), which here is (1, -16).

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step-by-step explanation: