If Circle A has a radius that is five more than twice as long as the radius of circle B and the sum of the diameters of the circle is 88 inches, find the area and circumference of circle A

Circumference of a circle A =

Area of a circle A = 12081.1 square inches

Step-by-step explanation:

Let denotes radius of circle B.

Circle A has a radius that is five more than twice as long as the radius of circle B.

So,

Radius of circle A =

Diameter of circle = 2 (radius of circle)

So,

Diameter of circle B = 2r

Diameter of circle A =

Sum of the diameters of the circles A and B =

As sum of the diameters of the circles is 88 inches,

inches

Radius of a circle A =

                                inches

Let R denotes radius of a circle A.

R = 62 inches

Circumference of a circle

Area of a circle square inches

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.