In 1910, halley's comet traveled close to earth about 1/7 of the distance from the earth to the sun. Earth's distance from the sun is 149.6 million kilometers. ( if u answer all them i'll give u brainliest but if not its alr) 1. How close was halley's comet to earth in 1910?create an equation to answer the question.

2. estimate the next 3 years when halley's comet will appear.

3. the core of halley's comet is oblong in shape, with its longest dimension 16 km long. earth's diameter is about 12,700 km . how many times larger in diameter is earth than halley's comet?

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

can you make your screen more see able?

then i might be able to .