The fare for taxi journeys in a certain town is $2.00 plus $1.00 for each kilometre. Using this information, estimate: (i) The fare for a journey of 3.5 km. (ii) The distance travelled if the fare was $6.00​

Step-by-step explanation:

Since the journey initially costs $2 (this will be our y-intercept), and the variable (x) is $1 for every additional kilometer. This can be modelled as...

y=1x+2

(i) if we want to know the cost of what 3.5 km would cost, we simply plug it into our equation...

y=1(3.5)+2

$5.5

(ii) For this question you can set the y value equal to 6 and plug in a random number for x until you get 6 on both sides. In this case...

6=1x+2

6=1(4)+2

The distance traveled if the fare was $6 is 4km

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how am i supposed to answer

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752