The following MINITAB output presents the results of a hypothesis test for a population mean μ. One-Sample Z : X
Test of mu = 73.5 vs not = 73.5
The assumed standard deviation = 2.3634
Variable N Mean StDev SE Mean 95% 01 Z P
X 145 73.2461 2.3634 0.1963 (72.8614, 73.6308) -1.29 0.196
A. Is this a one-tailed or two tailed test?
B. What is the null hypothesis?
C. What is the P-value?
D. Use the output to compute the P-value for the test of H0 : μ ≥ 73.6 versus H1 : μ < 73.6.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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c

step-by-step explanation:

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divide the numbers

step-by-step explanation: