A cohort study of smoking and lung cancer was conducted in a small island population. There were a total of 1,000 people in the study, and the study was conducted over a ten year period. Four hundred were smokers and 600 were not. Of the smokers, fifty developed lung cancer. Of the non-smokers, 10 developed lung cancer. In order to measure the strength of association between smoking and lung cancer in this population, which measure of exposure-disease association would you use

A measure of exposure-disease association one could use is the odds ratio (OR)

Step-by-step explanation:

An Odds ratio (OR) is a statistical measure quantifying the level of association between two events such as an exposure and an outcome

The odds ratio gives the probability of outcome where there is a given amount of exposure

We have the table;

The odds ratio = (The number of smokers with the lung-cancer)/(The number of non-smokers with lung-cancer) ÷ (The number of smokers smokers without long cancer).(The number of non-smokers without long cancer)

∴ OR = (50/10) ÷ (350/590) = 59/7 = 8. ≈ 8.4

Therefore, a smoker is approximately 8.4 times more likely to develop lung cancer than a non-smoker.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368