Write the formula for the parabola that has x- intercepts (1.3,0) and (-1.3,0), and y- intercept (0,169).

Step-by-step explanation:

et me start by the following correction:

The y intercept is (0,1.69) and not (0,169)

So the intercept form of the quadratic equation is y=a(x-p)(x-q)

where (-1.3,0)=(p,0) and (1.3,0) is (q,0); then p=-1.3, and q=1.3

With the vertex being at the y axis and the intercepts at the x axis means that the parabola opens down. then 1.69=a(0+1.3)(0-1.3), 1.69=-1.69 a, a=-1

Substituting, y=-1(x+1.3)(x-1.3) note that this is difference of two squares y=-[x2-(1.3)2] , y=-(x2-1.69), y=-x2+1.69

for the points! : )

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph