What is an equation of the line that passes through the point -5,7 and is parallel to the line x-5y=15

Step-by-step explanation:

Let line to be found be Line 2

Given:

Line 1

x - 5y = 15

x - 15 = 5y

Therefore slope = 1/5

Line 2

Point = (-5,7)

Slope = 1/5

Therefore: 7 = (1*-5)/5 + c

=> 7 = -1 + c

=> c = 8

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2