Can any of you guys help

5

Step-by-step explanation:

Pythagoras theorem is a² = b² + c² (where a is the hypotenuse or the longest side)

To find the shorter side, you rearrange it so it becomes c² = a² - b² (whether it is c or b doesn't matter)

So √13² - 12² = 5

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i believe that the slope of the line is -5

step-by-step explanation: