● The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distance travelled by their tips in 2 days. Class - 10th

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Step by step explanation please ​

Step-by-step explanation:

In 2 days, the short hand will complete 4 rounds.

∴ Distance moved by its tip 4(circumference of a circle of radius 4 cm)

=> 4×(2×22/7×4) cm

In 2 days, the long hand will complete 48 rounds.

∴ Distance moved by its tip 48(circumference of a circle of radius 6 cm)

=> 48×(2×22/7×6)cm = 12.672cm

Hence,

sum of distances moved by the tips of two hands of the clock

=> (704/7+12672)cm = 1910.85cm

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.