Determine whether each ordered pair is a solution of the system of linear equations. 3y = 6x + 12
2x - y = -4
a. (-3,2)
b. (0,4)
a. Is (-3,2) a solution?
0 Yes
Ο Νο
b. Is (0,4) a solution?
O No
0 Yes

(0,4)

Step-by-step explanation:

The given equations are :

3y = 6x + 12  

2x - y = -4

If (-3,2) be the solution of the above equations,

3(2) = 6(-3) + 12

6 = -18+12

6≠ -6  

2x - y = -4

2(2) -(-3) =-4

4+7 = -4

11 ≠ -4

No, (-3,2) is not the solution.

Similarly, put (0,4) in the abve equations,

3(4) = 6(0) + 12

12 = 12

and

2(0) - 4 = -4

-4 = -4

Hence, (0,4) is a solution of the given equations.

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.