10 minus the sum of 2 and 3Solution: 33 times the difference of 4 and 2Solution: 5t he difference of 5 and 2, times 3Solution: 724 divided by the product of 6 and 2Solution: 912 minus half the sum of 6 and 4Solution: 113 times the sum of 4 and 1, minus 9Solution: 210 minus the product of 2 and 3Solution: 4t he sum of 3 and 5, divided by 4Solution: 65 plus the difference of 9 and 4Solution: 88 plus the quotient of 27 and 3Solution: 10t he sum of 4 and 1__2, multiplied by 2Solution: 12half the product of 3 and 6, plus 2Solution: Write an expression for each phrase. Then solve the problem.13Could you write the expression for problem 2 without parentheses? Explain.

the probability is 0

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.