Arectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration about the y and x axes.

First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.





Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.

Answers: the graph is translated down 1 unit and the domain and range of g(x) is the same as the domain and range of f(x).