a stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where s(t) = 4.9t^2 + 29.4 and t is in seconds. if a stone is thrown downward at 29.4m/sec from a height of 132.3 m, how long will it take the stone to hit the ground?

t = 9 s

Step-by-step explanation:

A stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where

We need to find when the stone will hit the ground. It means when s(t) = 0. So,

So, the stone will take 9 seconds to hit the ground. Hence, this is the required solution.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.