1. The equation of circle Q is x² - 6x + y2 +8y+5 = 0. Write the equation of the line tangent to circle Q at (-1,-6) in point-slope form.

t is of interest to find the equations of the tangent to x^2+y^2=10 at (a,b) where the point is on the curve.

Taking the derivative,  2+2′=0⇒′=− , and so the slope of the tangents are  =− .

The equation of the tangent looks like

=−+⇒=−2+⇒=2+2=10

The equation becomes, +=10 .

Now use this formula.

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!