Find all solutions to tan(theta)=(square root)3

Tanθ = √3 = √3 / 1 

using a^2 + b^2 = c^2, the hypotenuse, the c = 2 
So, draw this triangle, and you quickly notice that the angle is at π/3 radians or 60degrees and 4π/3 or 240degrees. 

mathemaically... 

tanθ = √3 
tan^-1 √3 = θ 
θ = π/3, 4π/3 
or...in degrees, 
θ = 60, 240 

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