Mathematics, 13.11.2019 05:31 jacesmokesloud7254
Solve the following system equations:
2x + 4y β 3z = β7
3x + y + 4z = β12
x + 3y + 4z = 4
posibble answers:
(β6, 2, 1)
(6, 2, 1)
(6, β2, β1)
(β6, β2, β1)
Answers: 3
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Solve the following system equations:
2x + 4y β 3z = β7
3x + y + 4z = β12
x + 3y...
2x + 4y β 3z = β7
3x + y + 4z = β12
x + 3y...
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