You roll 1 red and 1 white dice. what is the probability that the number on the red die is larger than the number on the white die?
can anyone me? : (

I have my solution here with a different question:

What is the probability that the number on the red die is smaller than the number on the white die?

5/12 

There are 36 possible ways of throwing a dice twice. If the first throw is 1, then there are five possibilities for a greater throw in the second; if the first throw is 2, then there are four, and so on. 

Thus the total number where the second throw is greater than the first is 5 + 4 + 3 + 2 + 1 + 0 = 15, so the probability is 15 / 36 = 5 / 12 
There is a 5/6 chance that the dice are different. 
There is a 1/2 chance that the first will be bigger for two different dice. 
The probability is 5/6 x 1/2 = 5/12

I hope the method and technique in my solution might help you solve your problem.