Which describes the difference between the two sequences? First Sequence: 3, 6, 9, 12, ...
Second Sequence: 3, 12, 48, 192, ...
The first sequence is geometric because there is a common difference of 3. The second sequence is arithmetic
because there is a common ratio of 4.
O The first sequence is arithmetic because there is a common difference of 3. The second sequence is geometric
because there is a common ratio of 4.
The first sequence is arithmetic because there is a common ratio of 3.
The second sequence is geometric because there is a common difference of 4.
O The first sequence is arithmetic because there is a common difference of 4. The second sequence is geometric
because there is a common ratio of 3.

the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

Step-by-step explanation:

In this question table is given as

n          1          2         3           4            5

f(n)     48       -96      192      -385       768

We have to find out if the sequence is arithmetic or geometric.

For Arithmetic sequence :

Difference should be common in each term of fees.

common difference  = f(2) - f(1)

= -96 -48 = -144

similarly  = f(3) - f (2) = 192 + 96 = 288

Here,  ≠  so the sequence is not an arithmetic sequence.

For Geometric sequence :

Ratio  should be common in each term of f(n)

Common ratio  =

Therefore, the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

(a) the volume of the cone is 20/3 in3

hence, option a is correct.