What is the volume of a sphere with a radius of 60.5 ft, rounded to the nearest tenth of a cubic foot?

If rounded to the nearest tenth of a cubic foot, would be: 927587.2

Step-by-step explanation:

The equation of finding the equation of the volume of a sphere is "4π"

If values are inserted in for radius as 60.5, the answer will be 927587.2 when rounded to the nearest tenths.

Hope this helps!

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,