Use the graph of f(x) to explain the relationship between the real zeros of f(x) and its intercept(s). f(x) has one real zero at -2 because the graph of the function has an intercept at (0, -2). O f(x) has two real zeros at -4 and -2 because the graph of the function has intercepts at (-4, 0) and (0, -2). Of(x) has no real zeros because the graph of the function does not pass through (0, 0). f(x) has one real zero at -4 because the graph of the function has an intercept at (4,0).​