Suppose the variable x is represented by a standard normal distribution. What value of x is at the 70th percentile of the distribution? Equivalently, what is the value for which there is a probability of 0.70 that x will be less than that value? Please round your answer to the nearest hundredth.

486in is correct

step-by-step explanation:

answer: the answer is 100 x 12,500, which is 1,250,000.

step-by-step explanation: emily solved for a part when she should have solved for the whole.  

875,000 should be the numerator of the equivalent ratio.  

70 x 12,500 is 875,000.  

can you post a picture or something

option c is correct.

step-by-step explanation:

the rule regarding the sides of triangle is:

(length of longest side)^2 = square of sum of other two sides.

the sides given are:

6, 10 and 8.

applying the rule we will get:

(10)^2 = (6)^2 + (8)^2

100 = 36+64

100 = 100

so, her answer is incorrect.

no, she should have added 6^2 and 8^2 and compared that to 10^2.

so, option c is correct.