Please help.. j
Graph h(x) = 2 sin (2x) - 3.

Use 3.14 for it.

Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum
value on the graph closest to the first point.

Step-by-step explanation:

The midline is when y = -3, since that is the constant you are adding. This occurs when sin(2x) = 0, which occurs at x = 0. Here, the first point on the midline would be (0,-3).

To solve for a maximum, we need to find a value of x in which sin(2x) = 1. This occurs at pi/4, meaning we have a maximum at (pi/4, -1).

The next point would also be on the midline at pi/2, which would be (pi/2, -3).

The minimum would occur at 3pi/4 (since the sine would be -1), and the point would be (3pi/4, -5).

The last point of a 5-point summary would also be on the midline, at x = pi, (since the sine would be 0), and the point would be (pi, 0).

After this =, the sine tool function should sketch the rest of the graph.  

correct

step-by-step explanation:

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.