A=? C=?
1= 57, find angle 4
3= 63 find angle 2
2= 2x+6 and 3=3x-1 find x
AD=6cm and BD=12cm find BC

Step-by-step explanation:

1. m(angle A) is 90 degrees[ tangent drawn from the centre of the circle is always perpendicular to the circle]

2.m(angle C) is also 90 degrees[ tangent drawn from the centre of the circle is always perpendicular to the circle]

3. m(angle 1) is 57 degrees, angle A is 90 degrees, (given)

m(angle 4) + m(angle 1) + angle A = 180 [ sum of measures of a triangle is always 180 degrees]

m(angle 4) = 180 - ( 57 + 90)

= 33 degrees

4. m(angle 3 ) is 63 degrees, m(angle C) is 90 degrees, [given]

m(angle 3) + m(angle 2) + angle C = 180 [ sum of measures of a triangle is always 180 degrees]

m(angle 2) = 180 - ( 63 + 90)

= 27 degrees

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

answer is x<