Can someone please explain the answer step by step pls.

a) x= 29, y= 87

b) x= 19, y= 45

Step-by-step explanation:

Q5. a) Let the first number be x and the second number be y.

The sum of 2 integers is 116.

x +y= 116 (1)

The second number is three times the first number.

y= 3x (2)

Substitute (2) into (1):

x +3x= 116

4x= 116

x= 116 ÷4

x= 29

Substitute x= 29 into (2):

y= 3(29)

y= 87

b) Let the smaller number be x and the larger number be y.

x +y= 64 (1)

y -x= 26 (2)

Since we have to use substitution to solve the equations, let's first rewrite an equation to make one of the variables the subject of the equation.

From (1):

x= 64 -y (3)

Substitute (3) into (2):

y -(64 -y)= 26

y -64 +y= 26 (expand bracket)

2y= 26 +64 (simplify, +64 on both sides)

2y= 90

y= 90 ÷2

y= 45

Substitute y= 45 into (3):

x= 64 -45

x= 19

is means division by fractions

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)