The coordinates of point A are (6, 2). The coordinates of point B are (2, 6). AB¯¯¯¯¯is transformed to form ​A′B′¯¯¯¯¯¯¯​, shown in the graph. What is the transformation of ​AB¯¯¯¯¯​ that results in ​A′B′¯¯¯¯¯¯¯​? Drag and drop the answers into the boxes to complete the sentence. ​AB¯¯¯¯¯​ is Response area Response area to form ​A′B′¯¯¯¯¯¯¯​ . A graph with a line between points A begin ordered pair -6, 2 end ordered pair and B begin ordered pair -2, 6 end ordered pair

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9

3xy cannot be combined with the others

2x, -5x and x are like terms

im super bad at school but u for some reason need to have points to ask questions and you get points by answering so thats all im doing sorry for t r o l l i n g  

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