Prove that if triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides, their associated Saccheri quadrilaterals are congruent. (HINT: Recall that the angle sum for a triangle is equal to the sum of the measures of the summit angles of its associated Saccheri quadrilateral and that the two summit angles of a Saccheri quadrilateral are congruent.)

According to theorem 7.5

Π ABB'A' ≅ Π DEE'D'  

therefore by transitivity of equivalence  it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides

Step-by-step explanation:

To prove that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides :

Assume:  б(Δ ABC ) =  б(Δ DEF ) and also AB ≅ DE

let Π ABB'A' and DEE'D' be taken as the saccheri quadrilaterals that corresponds to Δ ABC and Δ DEF  respectively

Following the Lemma above; б(Π ABB'A' ) = б( Π DEE'D' ) given that

AB = summit of ABB'A' and DE = summit of DEE'D'  also  AB ≅ DE

According to theorem 7.5

Π ABB'A' ≅ Π DEE'D'  

therefore by transitivity of equivalence  it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides

attachment?

step-by-step explanation:

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.