Write the equation of a line parallel to f(x)=1/2x+1 and passing through the point (-5, -2).

y = 1/2x + 1/2

Step-by-step explanation:

y = 1/2x + b  [Parallel lines have the same slope but different y-intercepts]

-2 = (1/2)(-5) + b  [Plug in the coordinates (-5,-2) to find the y-intercept b]

b = 1/2  [Solve for b]

y = 1/2x + 1/2

y= 1/2x + 0.5

Step-by-step explanation:

plug in the x and y values to get the y-intercept the slope stays the same. hope this helps! :P

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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step-by-step explanation: