Joseph flew home from vacation with a heavy bag. With the first airline he flew, Joseph had to pay $27 to check his bag, plus $24 for every kilogram that his bag was over the weight limit. The next flight was with another airline that had the same weight limit. Joseph had to pay $25 per kilogram that his bag was over the weight limit, in addition to the checked bag fee of $16. By coincidence, the fees ended up being the same with both airlines. How far over the weight limit was the bag

Step-by-step explanation:

Flight A :

Checked bag fee = $27

Additional fee per overweight limit = $24

Flight B:

Checked bag fee = $16

Additional fee per overweight limit = $25

Since, the total amount paid for the package on both flights are the same ;

Let x = mass of bag above the weight limit.

Hence, Mathematically ;

27 + 24x = 16 + 25x

24x - 25x = 16 - 27

-x = -11

x = 11

Hence. The bag was s 11kg over the weight limit.

i can

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.