6.39 ÷ 0.09 = 82.14 ÷ 0.6 ≅
82.14 ÷ 0.6 =
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Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

How do i solve uniform motion problems?

If the value of cos330°is√3/2 then find cos 165°.