The edges of the bases of the frustum of a regular square pyramid have length 5 and 9, and the slant height of the frustum is 6. What is the Volume of the frustum?

i think the answer is b

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

i belive the biggest ratio would be 18: correct me if im wrong

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