please help me with these problems. please answer all the questions with the method I already started with... due at 11:59pm TODAY

Step-by-step explanation:

Howdy, did you do a, b, and c by yourself? Because there are some slight issues, so I'll do my best to explain.

a. 3x+5x

We know that x=2, so we can substitute 2 in for x right now, or we can combine like terms.

3x and 5x both have the variable x so we can add them easily to get 8x. If you substitute in 2, you're just multiplying 8×2, which is 16.

b. 5z+4z+z

Again, since

we know that z=-3, we can substitute in now, or we can combine like terms first. 5z, 4z, and z all have the variable x, we addition is easy. 5+4+1=10, so you'll have 10z. Substitute in -3 for z, and you're just multiplying 10×-3=-30

c. 3x+6+5x

This is trickier since 6 doesn't have the variable x. So to combine like terms means to only add 3x and 5x. So the equation will turn out looming like 8x+6. now substitute in 2 for x and you get

8(2)+6

16+6

22

d. 8y+8-4y

Combine like terms

4y+8

substitute in 5 for y

4(5)+8

20+8

28

e. 5z-4z+z

combine like terms

z+z

2z

substitute -3 for z

2(-3)

-6

f. 3x+6+5x-2

combine like terms

(so that's 3x+5x and 6-2)

8x+4

substitute in 2 for x

8(2)+4

16+4

20

g. 8y+8-4y-3

combine like terms

8y-4y+8-3

4y+5

substitute in 5 for y

4(5)+5

20+5

25

h. 5z-4z+z-3z

combine like terms

-z

substitute in -3 for z

-(-3)

double negatives make a positive

3

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.