In a distribution of 200 values, the mean is 50 and the standard deviation is 5. Assuring the distribution is normal, what percent of your values will fall between 45 and 65? : 95.005

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.