PLEASE I WILL DO ANYTHING JUST I NEED TO GET THIS LAST QUESTION DONE

= 158 square inches

STEP BY STEP:

okay! so basically I like to ignore the net figure (just my personal opinion)

so we know that the rectangular prism has six sides (one top, one bottom, one front, one back, and two on each side)

so using that information, we can solve for the surface area!

FRONT AND BACK AREA:

- to solve for this area, we are going to take the 8" and multiply it by 5" to find the surface area of the front and the back panels

8*5 = 40 BUT WE HAVE TWO PANELS WITH THIS AREA

40*2 = 80

TOP AND BOTTOM AREA:

- to solve for this area, we are going to take 3" and multiply it by 8" to find the surface area of the top and bottom panels

3*8 = 24 BUT WE HAVE TWO PANELS WITH THIS AREA

24*2 = 48

SIDE AREA:

- to solve for this area, we are going to take 3" and multiply it by 5" to find the surface area of both the left and right sides

3*5 = 15 BUT WE HAVE TWO PANELS WITH THIS AREA

15*2 = 30

So now we have all of our areas and we will just add them together!

80+48+30

= 158 square inches

I hope this helped :)

158

Step-by-step explanation:

its the right answer trust me I just can't be asked to explain it

answer:

your answer is: c. 196 7/8 in^3.

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

=====================================

part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

=====================================

part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).