Solve the equation. 3x + 2(4x − 6) = 8x + 1

Please help :) also have a good day :D
What is the value for x?

Please enter fractional values in the form ‘a/b’. For example, an answer of will be entered as 3/4.
x =

3x + 2(4x − 6) = 8x + 1

3x + (8x-12)=8x+1

-12=19x+1

-11=19x

-11/19     (Im pretty sure i did this right but at the same time im not, im sorry if i got this wrong)

=13/3

Step-by-step explanation:

1. Distribute

3+2(4−6)=8+1

3+8−12=8+1

2. Combine like terms

3+8−12=8+1

11−12=8+1

3. Add 12 to both sides of the equation

11−12=8+1

11−12+12=8+1+12

4. Simplify

11=8+13

5. Subtract 8x from both sides of the equation

11=8+13

11−8=8+13−8

6. Simplify

3=13

7. Divide both sides of the equation by the same term

3=13

3x÷3=13÷3

8. Simplify

If you cancel terms that are in both the numerator and denominator you will get:

=13/3

I hope this helps

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64