NSC -- Grade 12 QUESTION 6
AC is a diameter of the circle with centre F.
LC, LG,
GF is perpendicular to AC.
AD I GC
F
G
B
Prove that:
6.1
AC = CD
BG
6.2
BC
AC
GA
6.3 GBCF is a cyclic quadrilateral.
6.4 If BC = 12 units and the radius of the circle is 10 units,
6.4.1 determine the length of AB
6.4.2 determine the length of GA.
TOTAI​

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

first one because it can't have a fraction in it

step-by-step explanation: