Consider the equation x^2-7x-8=0 and describe it's roots​

there are two different, real roots.  

Step-by-step explanation:

The coefficients of this quadratic are {1, -7, -8}.  Let's find the discriminant, b^2 - 4ac.  In this case a = 1, b = -7 and c = -8 and so the discriminant value is

(-7)^2 - 4(1)(-8), or 49 + 32, or 81.

Because the discriminant is positive, we know immediately that there are two different, real roots.  

We are not asked to find the roots, but let's do it anyway:

      -(-7) ± √81

x = => x = 8 and x = -2 (which are real and different from

              2                                           one another).

hope this .

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